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Proof step 17 from proof mod-nls-04 (previous step)

0 < j, abs(i % j) < j, i % j < i0, i0 + j ≤ 1 ⊦ i0 < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
i % j < i0, abs(i % j) < j, 0 < j, i0 + j ≤ 1, 0 ≤ i0 ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs% ⊦ i < j ↔ ¬ j ≤ i; (ss)