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Proof step 20 from proof mod-nls-04 (previous step)

i % j < i0, i0 + abs(j) ≤ 1 ⊦ j = 0, abs(i % j) < abs(j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 21:
⊦ j ≠ 0 → abs(i % j) = abs(i) % abs(j)
Proof step 22:
i % j < i0, i0 + abs(j) ≤ 1 ⊦ j = 0, abs(i) % abs(j) < abs(j)

Rule argument

spec: <toplevel> name: abs-shift seq: ⊦ j ≠ 0 → abs(i % j) = abs(i) % abs(j) subst: [j, i] → [j, i] flags: <all paths>

Additional information

Used terms: j, i