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Proof step 23 from proof mod-nls-04 (previous step)

i % j < i0, i0 + abs(j) ≤ 1, abs(j) ≤ abs(i) % abs(j) ⊦ j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: mod-les seq: ⊦ 0 < j → ¬ j ≤ i % j subst: [i, j] → [abs(i), abs(j)] flags: <all paths>

Additional information

Used simplifier rules: ⊦ 0 < abs(i) ↔ i ≠ 0; (s) Used terms: abs(i), abs(j)