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Proof step 2 from proof mod-nls (previous step)

j0 = 1 + ~ j, i % j < j0, j0 < 0 ⊦ j = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: mod-lezero: ⊦ 0 < j → ¬ j + i % j ≤ 0;%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-pos: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward) from specification int-basic1%forward-le-04: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward) from specification int-abs% ⊦ i < 1 ↔ i ≤ 0; (s)% ⊦ i < j - i0 ↔ i + i0 < j; (s)% ⊦ i + 0 = i; (s)% ⊦ i - j < i0 ↔ i < j + i0; (s)%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2% ⊦ i + ~ j = i - j; (s)