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Proof step 1 from proof mod-sub-02 (conclusion)
⊦ 0 ≤ i ∧ j < i ∧ 0 < j ∧ 0 ≤ i0 ∧ i0 * j ≤ i ∧ i < (i0 + 1) * j → i % j = i - i0 * j
System applied rule normalize
And obtained the following new goals
Proof step 2
:
j < i, 0 < j, i < (i0 + 1) * j, 0 ≤ i, 0 ≤ i0, i0 * j ≤ i ⊦ i % j = i - i0 * j
Rule argument
Additional information