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Proof step 2 from proof mod-two-01 (previous step)

i < 0 ⊦ i % 2 = 0, i % 2 + 1 = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: mod2-neg-odd: ⊦ j < 0 → (j % 2 = ~1 ↔ j % 2 ≠ 0);%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2% ⊦ (* j) = i0 + (* j0) ↔ j - j0 = i0; (s)