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Proof step 5 from proof mod-twoodd-01 (previous step)

0 < j, 0 ≤ j0 ⊦ (2 * j0 + 1) % (2 * j) = j0 % j * 2 + 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
0 ≤ i, 0 < j ⊦ (2 * i + 1) % (2 * j) = i % j * 2 + 1

Rule argument

spec: <toplevel> name: mod-twoodd seq: 0 ≤ i, 0 < j ⊦ (2 * i + 1) % (2 * j) = i % j * 2 + 1 subst: [j, i] → [j, j0] flags: <all paths>

Additional information

Used simplifier rules: ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j; (s) Used terms: j, j0