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Proof step 6 from proof mod-zero-06 (previous step)

0 < i, i < i / j * j, 0 < i / j * j, 1 < i / j * j, 0 ≤ i, abs(j) = 1 ∨ abs(j) ≤ i ⊦ j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ 0 ≤ i ∧ 0 < j → ¬ i < i / j * j
Proof step 8:
1 < i / j * j, 0 < i / j * j, i < i / j * j, 0 < i, 0 ≤ i, abs(j) = 1 ∨ abs(j) ≤ i ⊦ j = 0, 0 ≤ i ∧ 0 < j

Rule argument

spec: <toplevel> name: ls-same-pos-02 seq: ⊦ 0 ≤ i ∧ 0 < j → ¬ i < i / j * j subst: [j, i] → [j, i] flags: <all paths>

Additional information

Used terms: j, i