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Proof step 2 from proof modeq-neg-02 (previous step)

0 < j, i0 * j + j0 < 0, 0 ≤ j0 ⊦ (i0 * j + j0) % j = j0 % j - j, j0 % j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i0 < 0, i0 * j + j0 < 0, 0 < j, 0 ≤ j0 ⊦ j0 % j = 0, j0 % j = (i0 * j + j0) % j + j

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 ∧ 0 ≤ j → i < j; (s)%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult% ⊦ 0 < i → (i * j < 0 ↔ j < 0); (s)% ⊦ i + j < j ↔ i < 0; (s)%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ i - j = i0 ↔ i = i0 + j; (s)