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Proof step 14 from proof modex (previous step)

i % j = 0 ⊦ j = 0, 0 < j, ∃ j0. i = j0 * j, 0 < j ∧ ¬ i < 0, j < 0 ∧ ¬ i < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
i % j = 0, i < 0, j < 0 ⊦ ∃ j0. i = j0 * j

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs% ⊦ i < 0 ∧ 0 ≤ j → i < j; (s)% ⊦ i < j → ¬ j < i; (s)% ⊦ ¬ i < j → (i = j ↔ ¬ j < i); (ss)