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Proof step 2 from proof modex (previous step)

⊦ i % j = 0 ↔ (∃ j0. i = j0 * j), j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i % j = 0 ⊦ j = 0, ∃ j0. i = j0 * j

Rule argument

Additional information

Used simplifier rules: mod-mult-04: j ≠ 0 ⊦ (i * j) % j = 0;%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult