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Proof step 7 from proof modmod-mult-03 (previous step)

0 < j0, j < 0 ⊦ (i % (j * j0)) % j = i % j, j = 0, 0 < j ∧ 0 ≤ i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
0 < j0, j < 0 ⊦ (i % (j * j0)) % j = i % j, j = 0

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs% ⊦ i < j → ¬ j < i; (s)