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Proof step 1 from proof mult-01 (conclusion)

⊦ 0 ≤ i0 ∧ i0 < abs(j) ∧ j < 0 ∧ 0 ≤ i → (i * abs(j) + i0) / j = ~ i

System applied rule normalize

And obtained the following new goals

Proof step 2:
i0 < abs(j), j < 0, 0 ≤ i0, 0 ≤ i ⊦ (i * abs(j) + i0) / j = ~ i

Rule argument

Additional information