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Proof step 2 from proof mult-05 (previous step)

0 < i0, i0 < j, 0 < i ⊦ (j * i - i0) / j = i - 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
1 < j, 0 < i0, i0 < j, 0 < i, 0 < j ⊦ i = (j * i - i0) / j + 1

Rule argument

Additional information

Used simplifier rules: forward-pos: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward) from specification int-basic1%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ i - j = i0 ↔ i = i0 + j; (s)