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Proof step 2 from proof mult-div-switch (previous step)

i % j = 0 ⊦ i / j * j = i, j = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: divmult: j ≠ 0 ⊦ i % j = 0 → i / j * j = i;%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult