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Proof step 3 from proof nls-mult-div (previous step)

i1 < j, i < (i * i1) / j, 0 < j, 0 < (i * i1) / j, 0 ≤ i ⊦

User applied rule cut formula

And obtained the following new goals

Proof step 4:
i = 0, 0 < (i * i1) / j, 0 < j, i < (i * i1) / j, i1 < j, 0 ≤ i ⊦
Proof step 7:
0 < (i * i1) / j, 0 < j, i < (i * i1) / j, i1 < j, 0 ≤ i ⊦ i = 0

Rule argument

fma: i = 0

Additional information

Used formulas: i = 0