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Proof step 5 from proof nls-mult-div (previous step)

i1 < j, 0 < j, 0 < 0 / j ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ 0 ≤ i ∧ 0 < j ∨ i < 0 ∧ j < 0 → i / j = abs(i) / abs(j)

Rule argument

spec: <toplevel> name: abs-intro seq: ⊦ 0 ≤ i ∧ 0 < j ∨ i < 0 ∧ j < 0 → i / j = abs(i) / abs(j) subst: [j, i] → [j, 0] flags: <all paths>

Additional information

Used simplifier rules: zero: j ≠ 0 ⊦ 0 / j = 0;%zero: j ≠ 0 ⊦ 0 / j = 0;% ⊦ 0 < j → abs(j) = j; (s) Used terms: j, 0