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Proof step 2 from proof num-neg-01 (previous step)

j < 0 ⊦ i / j = ~(i / ~ j)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: neg: j ≠ 0 ⊦ i / ~ j = ~(i / j);% ⊦ ~ ~ i = i; (s)