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Proof step 2 from proof nummult-le-04 (previous step)

0 < i, 0 ≤ j ⊦ i * i0 ≤ j ↔ i0 ≤ j / i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ 0 < i ∧ 0 ≤ j → ((* i) * i0 ≤ (* j) ↔ i0 ≤ j / i)

Rule argument

spec: <toplevel> name: nummult-le seq: ⊦ 0 < i ∧ 0 ≤ j → ((* i) * i0 ≤ (* j) ↔ i0 ≤ j / i) subst: [j, i0, i] → [j, i0, i] flags: <all paths>

Additional information

Used simplifier rules: ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j; (s) Used terms: j, i0, i