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Proof step 10 from proof nummult-ls-03 (previous step)

j + 1 = i2 + i1, j < 0, i1 < 0, i1 ≤ j ⊦ j < i2 * i0 ↔ i1 / i2 < i0, 0 < i2 ∧ i1 < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
j + 1 = i2 + i1, i1 < 0, j < 0, i1 ≤ j, i2 ≤ 0 ⊦ j < i2 * i0 ↔ i1 / i2 < i0

Rule argument

Additional information

Used simplifier rules: forward-le-04: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward) from specification int-abs% ⊦ i < j ↔ ¬ j ≤ i; (ss)% ⊦ i < 0 ∧ 0 ≤ j → i < j; (s)