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Proof step 18 from proof nummult-ls-03 (previous step)

j0 < i2, 0 < i2, i3 * i2 + j0 < 0, abs(j0) < i2, i2 * (i3 + 1) + j0 ≤ 0, j0 ≤ 0 ⊦ i2 * (i3 + 1) + j0 ≤ i2 * i0 ↔ ¬ i0 ≤ i3

User applied rule case distinction

And obtained the following new goals

Proof step 19:
abs(j0) < i2, i3 * i2 + j0 < 0, 0 < i2, j0 < i2, i0 ≤ i3, j0 ≤ 0, i2 * (i3 + 1) + j0 ≤ 0, i2 * (i3 + 1) + j0 ≤ i2 * i0 ⊦
Proof step 22:
abs(j0) < i2, i3 * i2 + j0 < 0, 0 < i2, j0 < i2, j0 ≤ 0, i2 * (i3 + 1) + j0 ≤ 0 ⊦ i2 * (i3 + 1) + j0 ≤ i2 * i0, i0 ≤ i3

Rule argument

pos: right 1

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