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Proof step 4 from proof nummult-ls-03 (previous step)

j + 1 = i1 + i, 0 < i, j < 0 ⊦ j < i * i0 ↔ i1 / i < i0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ j = i0 + j0 ↔ j - i0 = j0
Proof step 6:
j + 1 - i1 = i, j < 0, 0 < i ⊦ j < i * i0 ↔ i1 / i < i0

Rule argument

spec: int-abs name: add-rew seq: ⊦ j = i0 + j0 ↔ j - i0 = j0 subst: [j0, i0, j] → [i, i1, j + 1] flags: <all paths>

Additional information

Used terms: i, i1, j + 1