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Proof step 2 from proof one-lez (previous step)

0 < i, 1 / i ≤ 0 ⊦ 1 / i = 0 ∧ 1 < i

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: div-lezero: ⊦ 0 < j → (i / j ≤ 0 ↔ i < j);%one-04: ⊦ 1 < j → 1 / j = 0;%i0 ≠ 0, i0 ≤ i ⊦ (* i) < j → (* i0) < j; (s)