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Proof step 3 from proof pdiv-ls (
previous step
)
i / j < j0, i / j < i0 / j, 0 < j, i0 ≤ i, j0 ≤ i0 / j ⊦
User applied rule insert lemma
And obtained the following new goals
Proof step 4
:
0 < i0 ⊦ i / i0 < j / i0 → i < j
Rule argument
spec: <toplevel> name: lsfc-01 seq: 0 < i0 ⊦ i / i0 < j / i0 → i < j subst: [i0, i, j] → [j, i, i0]
Additional information
Used simplifier rules: ⊦ i ≤ j → ¬ j < i; (s) Used terms: j, i, i0