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Proof step 20 from proof square-nle (previous step)

j < 2, 0 ≤ j ⊦ (j * (j + 1)) / 2 ≤ j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 21:
j < 2, j < (j * (j + 1)) / 2, 0 < (j * (j + 1)) / 2, 0 ≤ j ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ i ≤ j ↔ ¬ j < i; (ss)