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Proof step 4 from proof square-nle (previous step)

0 ≤ j, (j * (j + 1)) / 2 ≤ j ⊦ j < 2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
0 < j, (j * (j + 1)) / 2 ≤ j, 0 ≤ j, 2 ≤ j ⊦

Rule argument

Additional information

Used simplifier rules: forward-le: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward) from specification int-abs% ⊦ i < j ↔ ¬ j ≤ i; (ss)