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Proof step 2 from proof two-odd (previous step)

i % 2 = 0, 0 < i ⊦ (i - 1) / 2 = i / 2 - 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i % 2 = 0, 0 < i ⊦ i = 2 * ((i - 1) / 2 + 1)

Rule argument

Additional information

Used simplifier rules: two-even: ⊦ i % 2 = 0 → (i / 2 = j ↔ i = 2 * j);%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ i - j = i0 ↔ i = i0 + j; (s)