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Proof step 2 from proof zero-06 (previous step)

i < 0, j < 0 ⊦ j = 0, 0 ≤ i / j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
j < 0, i < 0, i / j < 0 ⊦ j = 0

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs% ⊦ i ≤ j ↔ ¬ j < i; (ss)