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Proof step 7 from proof zero (previous step)

0 < j ⊦ 0 / j = 0

User applied rule insert lemma

And obtained the following new goals

Proof step 8:
⊦ 0 ≤ i ∧ 0 < j → i / j * j ≤ i ∧ i < (i / j)+1 * j

Rule argument

spec: <toplevel> name: Div-def seq: ⊦ 0 ≤ i ∧ 0 < j → i / j * j ≤ i ∧ i < (i / j)+1 * j subst: [i, j] → [0, j]

Additional information

Used simplifier rules: ⊦ 0 < i → (i * j ≤ 0 ↔ j ≤ 0); (s)% ⊦ i ≠ j → (i ≤ j ↔ i < j); (s)%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult% ⊦ i +1 = i + 1; (s)% ⊦ 0 < i → (0 < i * j ↔ 0 < j); (s)% ⊦ (* j) < i0 + (* j0) ↔ j - j0 < i0; (s)% ⊦ ~1 < i ↔ 0 ≤ i; (s)% ⊦ i < j → ¬ j < i; (s)%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2 Used terms: 0, j