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Proof step 2 from proof case-40 (previous step)

i < 40, 30 ≤ i ⊦ i = 30, i = 31, i = 32, i = 33, i = 34, i = 35, i = 36, i = 37, i = 38, i = 39

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
1 < i, 0 < i, 30 < i, i < 40 ⊦ i = 30, i = 31, i = 32, i = 33, i = 34, i = 35, i = 36, i = 37, i = 38, i = 39

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-pos: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward) from specification int-basic1% ⊦ i ≠ j → (i ≤ j ↔ i < j); (s)