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Proof step 27 from proof case-40 (previous step)

1 < i, 0 < i, 30 < i, i < 32 ⊦ i = 30, i = 31, i = 32, i = 33, i = 34, i = 35, i = 36, i = 37, i = 38, i = 39

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 28:
⊦ i ≠ j -1 → (i < j ↔ i < j -1)

Rule argument

spec: int-basic1 name: ls-rec seq: ⊦ i ≠ j -1 → (i < j ↔ i < j -1) subst: [j, i] → [32, i] flags: <all paths>

Additional information

Used simplifier rules: i + 1 = i0 ⊦ j < (* i0) → ¬ (* i) < j; (s) Used terms: 32, i