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Proof step 11 from proof div-abs-02 (previous step)

i * i0 = j ⊦ j < 0, ∃ i0. i * i0 = j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
0 ≤ i * i0 ⊦ ∃ i1. i * i1 = i * i0

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs% ⊦ i < j ↔ ¬ j ≤ i; (ss)