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Proof step 3 from proof div-eq-one (previous step)

j / i = 1, i | j ⊦ i = 0, j = i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ i | j ↔ (∃ i0. i * i0 = j)

Rule argument

spec: <toplevel> name: divides seq: ⊦ i | j ↔ (∃ i0. i * i0 = j) subst: [j, i] → [j, i] flags: <all paths>

Additional information

Used simplifier rules: j ≠ 0 ⊦ (i * j) / j = i; (s)%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult% ⊦ i = 1 → i * j = j; (s) Used terms: j, i