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Proof step 6 from proof div-gcd-is-neg-01-01 (previous step)

i0 < 0, 0 ≤ i0 / gcd(i, i0), i0 / gcd(i, i0) ≤ 0 ⊦

User applied rule cut formula

And obtained the following new goals

Proof step 7:
i0 / gcd(i, i0) = 0, i0 < 0, i0 / gcd(i, i0) ≤ 0, 0 ≤ i0 / gcd(i, i0) ⊦

Rule argument

fma: i0 / gcd(i, i0) ≠ 0

Additional information

Used simplifier rules: div-gcd-is-neg-01: ⊦ i0 < 0 → ¬ 0 < i0 / gcd(i, i0);% ⊦ i ≠ j → (i ≤ j ↔ i < j); (s) Used formulas: i0 / gcd(i, i0) ≠ 0