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Proof step 3 from proof div-gcd-is-neg-01 (previous step)

i0 < 0, 0 < i0 / gcd(i, i0) ⊦

User applied rule apply lemma

And obtained the following new goals

Proof step 4:
⊦ i0 < 0 → i0 / gcd(i, i0) ≤ 0
Proof step 5:
0 < i0 / gcd(i, i0), i0 < 0, i0 < 0 → i0 / gcd(i, i0) ≤ 0 ⊦

Rule argument

spec: <toplevel> name: div-gcd-is-neg seq: ⊦ i0 < 0 → i0 / gcd(i, i0) ≤ 0 subst: [i0, i] → [i0, i]

Additional information

Used terms: i0, i