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Proof step 2 from proof div-gcd-neg-not-zero (previous step)

i0 / gcd(i, i0) = 0, i0 < 0 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i0 / gcd(i, i0) = 0, i0 < 0 ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs