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Proof step 4 from proof div-gcd-zero (previous step)

i / gcd(i, i0) = 0, gcd(i, i0) ≤ abs(i) ⊦ i = 0

User applied rule cut formula

And obtained the following new goals

Proof step 5:
i / gcd(i, i0) = 0, gcd(i, i0) ≤ abs(i) ⊦ i = 0, i0 = 0

Rule argument

fma: i0 = 0

Additional information

Used simplifier rules: gcd-zero-03: ⊦ i ≠ 0 → gcd(i, 0) = abs(i);% ⊦ i ≠ 0 → i / abs(i) ≠ 0; (s) Used formulas: i0 = 0