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Proof step 2 from proof div-mult-01 (previous step)

⊦ i * i0 | i * i1 ↔ i0 | i1, i = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: divides-mult: ⊦ j ≠ 0 → (i * j | j * i0 ↔ i | i0);%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult