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Proof step 1 from proof divides-mult (conclusion)
⊦ j ≠ 0 → (i * j | j * i0 ↔ i | i0)
System applied rule normalize
And obtained the following new goals
Proof step 2
:
⊦ i * j | j * i0 ↔ i | i0, j = 0
Rule argument
Additional information