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Proof step 18 from proof divides-prime (previous step)

i < 0, i0 < 0, 2 ≤ i0 * i, ∀ i1. 1 < i1 ∧ i1 < i0 * i → ¬ i1 | i0 * i ⊦ ~1 = i0, ~1 = i, i = 0, i0 = 0

User applied rule all left

And obtained the following new goals

Proof step 19:
i0 < 0, i < 0, 2 ≤ i0 * i, 1 < abs(i0) ∧ abs(i0) < i0 * i → ¬ abs(i0) | i0 * i, ∀ i1. 1 < i1 ∧ i1 < i0 * i → ¬ i1 | i0 * i ⊦ ~1 = i, ~1 = i0, i = 0, i0 = 0

Rule argument

pos: left 4 terms: abs(i0) abort: F discard: F computed: F

Additional information

Used terms: abs(i0)