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Proof step 4 from proof divides-prime (previous step)

prime(j), i | j ⊦ abs(i) = j, abs(i) = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
prime(j), i | j ⊦ abs(i) = 1, abs(i) = j

Rule argument

Additional information