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Proof step 3 from proof gcd-abs-rew (previous step)

⊦ gcd(i, abs(j)) = gcd(abs(i), abs(j))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ gcd(i, j) = gcd(abs(i), abs(j))

Rule argument

spec: <toplevel> name: gcd-abs-rew-02 seq: ⊦ gcd(i, j) = gcd(abs(i), abs(j)) subst: [j, i] → [abs(j), i] flags: <all paths>

Additional information

Used simplifier rules: ⊦ abs(abs(i)) = abs(i); (s) Used terms: abs(j), i