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Proof step 24 from proof gcd-conq-one (previous step)

1 = i * i0 + j0 * j, gcd(i, j) = 1, i0 < 0, 0 < i, 0 ≤ j * j0 + i0, 0 ≤ j ⊦ i = 0, j | i * (j * j0 + i0) - 1

User applied rule insert equation

And obtained the following new goals

Proof step 25:
1 = i * i0 + j0 * j, gcd(i, j) = 1, 0 < i, i0 < 0, 0 ≤ j, 0 ≤ j * j0 + i0 ⊦ i = 0, j | i * (j * j0 + i0) - i * i0 + j0 * j

Rule argument

pos: left 1 flags: [[2,2,2,2]]

Additional information