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Proof step 10 from proof gcd-div-gcd-pos (previous step)

i = i1 * gcd(i, j), 0 < j, 0 < i, 0 < i0, 1 < i0, 0 < gcd(i, j), i0 | i1, i0 | j / gcd(i, j), 0 ≤ i, 0 ≤ i1 ⊦

User applied rule insert elim lemma

And obtained the following new goals

Proof step 11:
i = i1 * gcd(i, j), j = i2 * gcd(i, j) + j0, 0 < gcd(i, j), 1 < i0, 0 < i0, 0 < i, 0 < j, j0 < gcd(i, j), i0 | i2, i0 | i1, 0 ≤ i1, 0 ≤ i, 0 ≤ j0, 0 ≤ i2, 0 ≤ j ⊦

Rule argument

spec: int-div name: div-elim-pospos seq: ⊦ 0 < j ∧ 0 ≤ i → ( i0 = i / j ∧ j0 = i % j ↔ i = i0 * j + j0 ∧ 0 ≤ j0 ∧ j0 < j ∧ 0 ≤ i0) subst: [i, j, i0, j0] → [j, gcd(i, j), i2, j0]

Additional information

Used simplifier rules: ⊦ i ≤ j ↔ ¬ j < i; (ss)% ⊦ i < j → ¬ j < i; (s)%⊦ 0 < j ∧ 0 ≤ i → ( i0 = i / j ∧ j0 = i % j ↔ i = i0 * j + j0 ∧ 0 ≤ j0 ∧ j0 < j ∧ 0 ≤ i0); (elim) Used terms: j, gcd(i, j), i2, j0