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Proof step 1 from proof gcd-div-rest (conclusion)

⊦ abs(j0) < gcd(i, j) → (i = i1 * gcd(i, j) + j0 ↔ i = i1 * gcd(i, j) ∧ j0 = 0)

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information