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Proof step 10 from proof gcd-mod-one (previous step)

i * i0 = j * i1 + 1, gcd(i, j) = 1, 1 < i, 0 < i, 1 < j, 0 < j, 0 ≤ i0 ⊦ (i * i0) % j = 1

User applied rule cut formula

And obtained the following new goals

Proof step 11:
i * i0 = j * i1 + 1, gcd(i, j) = 1, 0 < j, 1 < j, 0 < i, 1 < i, i1 < 0, 0 ≤ i0 ⊦ (i * i0) % j = 1
Proof step 15:
i * i0 = j * i1 + 1, gcd(i, j) = 1, 0 < j, 1 < j, 0 < i, 1 < i, 0 ≤ i0 ⊦ (i * i0) % j = 1, i1 < 0

Rule argument

fma: i1 < 0

Additional information

Used formulas: i1 < 0