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Proof step 18 from proof gcd-mult-pos (previous step)

0 < j, i < j, 0 < i1, 0 < i, 1 < j, 0 ≤ j, ∀ j0, i0, i2. i→n(j0 * i0 + i2 * i0) < i→n(j * i1 + i * i1) → 0 < i2 ∧ 0 < i0 ∧ 0 ≤ j0 → gcd(i2 * i0, j0 * i0) = gcd(i2, j0) * i0 ⊦ gcd(i * i1, j % i * i1) = gcd(i, j % i) * i1, i = 0, i1 = 0, i→n(j % i * i1 + i * i1) < i→n(j * i1 + i * i1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
1 < j, 0 < i, 0 < i1, i < j, 0 < j, 0 ≤ j, abs(j * i1 + i * i1) ≤ abs(j % i * i1 + i * i1), ∀ j0, i0, i2. i→n(j0 * i0 + i2 * i0) < i→n(j * i1 + i * i1) → 0 < i2 ∧ 0 < i0 ∧ 0 ≤ j0 → gcd(i2 * i0, j0 * i0) = gcd(i2, j0) * i0 ⊦ gcd(i * i1, j % i * i1) = gcd(i, j % i) * i1, i = 0, i1 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ↔ ¬ j ≤ i; (ss)% ⊦ i→n(i) < i→n(j) ↔ abs(i) < abs(j); (s)