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Proof step 8 from proof gcd-mult (previous step)

⊦ gcd(abs(i) * abs(i1), abs(j) * abs(i1)) = gcd(i, j) * abs(i1), i = 0, i1 = 0, j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ gcd(i, j) = gcd(abs(i), abs(j))
Proof step 10:
⊦ gcd(abs(i) * abs(i1), abs(j) * abs(i1)) = gcd(abs(i), abs(j)) * abs(i1), i = 0, i1 = 0, j = 0

Rule argument

spec: <toplevel> name: gcd-abs-rew-02 seq: ⊦ gcd(i, j) = gcd(abs(i), abs(j)) subst: [j, i] → [j, i] flags: <all paths>

Additional information

Used terms: j, i