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Proof step 8 from proof gcd-primes (previous step)

1 < i0, 0 < i0, prime(i), prime(j), i0 | i, abs(i0) = j ∨ abs(i0) = 1 ⊦ i = j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
0 < j, 1 < j, prime(j), prime(i), j | i ⊦ i = j, j = 1

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-pos: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward) from specification int-basic1% ⊦ 1 < i → abs(i) = i; (s)