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Proof step 47 from proof gcd-rec-sub-01 (previous step)

⊦ gcd(i, i0 + i) = gcd(i, i0), i = 0, i0 = 0, i < 0, 0 < i ∧ i < i0 + i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 48:
0 < i ⊦ gcd(i, i0 + i) = gcd(i, i0), i0 = 0, i < i0 + i

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ i < j → ¬ j < i; (s)% ⊦ ¬ i < j → (i = j ↔ ¬ j < i); (ss)